var x {1..2} >= 0;

minimize obj: 
  (x[1] - 2)^2 + x[2]^2
  ;

subject to constr1: (1-x[1])^3 >= x[2];

let x[1] := -2;
let x[2] := -2;

#printf "optimal solution as starting point \n";
#let x[1] := 1;
#let x[2] := 0;

solve;

display x;

display obj;

display obj - 1;